The equations represent the law of sines correctly would be option D that is [tex][b \times\dfrac{ sin (A) }{ sin (B)}] = a[/tex].
For any triangle ABC, with side measures |BC| = a. |AC| = b. |AB| = c,
we have, by law of sines,
[tex]\dfrac{sin\angle A}{a} = \dfrac{sin\angle B}{b} = \dfrac{sin\angle C}{c}[/tex]
Remember that we took
[tex]\dfrac{\sin(angle)}{\text{length of the side opposite to that angle}}[/tex]
The law of sines is can be written as
[tex]\dfrac{sin\angle A}{a} = \dfrac{sin\angle B}{b} = \dfrac{sin\angle C}{c}[/tex]
which can be manipulated algebraically as
[tex][b \times\dfrac{ sin (A) }{ sin (B)}] = a[/tex]
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