The solution of the given equation represented in the task content can be determined by first evaluating the LCM and hence is; y= 27.
What is the solution of the equation as given in the task?
The given equation is; (y-5)/2=(y+6)/3.
Hence, by multiplying the equation by 6, we have;
3(y-5) = 2(y+6)
3y -15 = 2y +12
y = 27.
Hence, it follows that the value of y which is a solution to the equation is; y = 27.
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