Answer:
[tex](x+2)^2+(y-9)^2=[/tex] 90
Step-by-step explanation:
The centre is (-2,9) so the first part of the equation will be (x+2)^2 + (y-9)^2 and to get the second half, you know the point on the circle which you can use to find the radius. So the triangle formed would be 3 long, 9 high and using Pythagoras you can do:
[tex]3^2+9^2=r^2[/tex]
9+81= [tex]r^2\\[/tex]
90 = [tex]r^2[/tex]
and this equation ends with r^2 so you can substitute that back into the equation so together it will be
[tex](x+2)^2+(y-9)^2=[/tex] 90
