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  • 03-07-2018
  • Chemistry
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What volume of a 0.580-m solution of cacl2 contains 1.28 g solute?

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PBCHEM
PBCHEM PBCHEM
  • 12-07-2018

Answer : 19.9 mL


Explanation : We have the moles of Calcium chloride and the weight of it as 1.28 g,


Here, molarity has to be related with the volume so, 0.580 M = 0.580 mol/L


so now in 1.28 g there will be : 1.28 X (1 g / 111 mol of calcium chloride) = 0.01153 mol


Now, we can find out the volume from this;


0.01153 mol X (1 L / 0.580 mol) X (1000 mL / 1 L) = 19.9 mL


Hence, the volume will be 19.9 mL


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