ssdawg1 ssdawg1
  • 01-06-2018
  • Mathematics
contestada

type the expression as radicals 5/y2

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jdoe0001 jdoe0001
  • 01-06-2018
[tex]\bf \cfrac{5}{y^2}\qquad \begin{cases} \sqrt{25}=5\\ \sqrt{(y^2)^2}=y^2 \end{cases}\implies \cfrac{\sqrt{25}}{\sqrt{(y^2)^2}}\implies \cfrac{\sqrt{25}}{\sqrt{y^4}}\implies \sqrt{\cfrac{25}{y^4}}[/tex]
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